At half power points of a resonance curve, the current is

This question was previously asked in
KVS TGT WET (Work Experience Teacher) 8 Jan 2017 Official Paper
View all KVS TGT Papers >
  1. 2 times the maximum current.
  2.  times the maximum current.
  3. 0.707 times the maximum current.
  4. 1.414 times the maximum current.

Answer (Detailed Solution Below)

Option 3 : 0.707 times the maximum current.
Free
KVS TGT Mathematics Mini Mock Test
70 Qs. 70 Marks 70 Mins

Detailed Solution

Download Solution PDF
Key Points

 At half-power points of a resonance curve, the current is 0.707 times the maximum current.

Important points regarding half-power points are:

  • The current is Imax/√2.
  • Impedance is √2 R or √2 Zmin.
  • The circuit phase angle → ±45° or π/4 rad

 

Latest KVS TGT Updates

Last updated on May 8, 2025

-> The KVS TGT Notiifcation 2025 will be released for 16661 vacancies.

-> The application dates will be announced along with the official notification.

-> Graduates with B.Ed or an equivalent qualification are eligible for this post.

-> Prepare with the KVS TGT Previous Year Papers here.

Hot Links: real cash teen patti teen patti game paisa wala teen patti sweet happy teen patti teen patti gold apk download