An integrator contains a 100 kΩ and 1 μF capacitor. If the voltage applied to the integrator input is 1 V, what is the voltage present at the integrator output after 1 s?

Question

Question

This question was previously asked in

MPPKVVCL Jabalpur JE Electrical 16 August 2018 Official Paper

Answer 1

The correct answer is option 4):(10 V)

Concept:

The integrator circuit is shown as

F2 U.B D.K 28.09.2019 D 2

Resistance (R) = 100 kΩ

Capacitance (C) = 1 μF

Integrator input voltage (Vi) = 1 V

For an integrator-type DVM, the output voltage is given by

\({V_0} = - \frac{1}{{RC}}\mathop \smallint \limits_0^t {V_i}dt\)

\(= - \frac{1}{{100 \times {{10}^3} \times 1 \times {{10}^{ - 6}}}}\mathop \smallint \limits_0^1 1dt = - 10\;V\)