Question
Download Solution PDFA computer system has a 4 K word cache organized in a block-set associative manner with 4 blocks per set, 64 words per block. The numbers of bits in the SET and WORD fields of the main memory address formula are respectively:
This question was previously asked in
ESE Electronics 2013 Paper 2: Official Paper
Answer (Detailed Solution Below)
Option 4 : 4 and 6
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ST 1: UPSC ESE (IES) Civil - Building Materials
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Detailed Solution
Download Solution PDF\(\# \;blocks = \frac{{4K}}{{64}} = 64\)
\(\# \;sets = \frac{{64}}{4} = 16\)
⇒ 4 bits for SET
Each block has 64 words
⇒ 6-bits required for word.
Tag |
Set |
Word |
|
(4)Bit |
(6)Bit |
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