A computer system has a 4 K word cache organized in a block-set associative manner with 4 blocks per set, 64 words per block. The numbers of bits in the SET and WORD fields of the main memory address formula are respectively:

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  1. 15 and 4
  2. 6 and 4
  3. 7 and 2
  4. 4 and 6

Answer (Detailed Solution Below)

Option 4 : 4 and 6
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\(\# \;blocks = \frac{{4K}}{{64}} = 64\) 

\(\# \;sets = \frac{{64}}{4} = 16\) 

⇒ 4 bits for SET

Each block has 64 words

⇒ 6-bits required for word.

Tag

Set

Word

 

(4)Bit

(6)Bit

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