A cam displaces its follower by 20 mm through simple harmonic motion (SHM). The cam is rotating at 15 RPM and its angle of rise is 90°. The time period of the SHM will be

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BPSC AE Paper 6 (Mechanical) 2019 Official Paper
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  1. 4 seconds
  2. 2 seconds
  3. 1 seconds
  4. 0.5 second

Answer (Detailed Solution Below)

Option 3 : 1 seconds
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Detailed Solution

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Explanation:

  • Cam is a mechanical element which is used to deliver the reciprocating or oscillating motion to another machine element known as a follower.
  • simple harmonic motion of constant amplitude in which the acceleration is proportional and oppositely directed to the displacement of the body from a position of equilibrium.
  • A simple harmonic motion curve is widely used since it is simple to design. The curve is the projection of a circle about the cam rotation axis as shown in the figure.

where H = maximum height of follower in SHM motion

Calculation:          

Given:

Displacement of follower in SHM = 20 mm, angle of rise  θ = 90o = π /2, speed of cam rotation  N = 15 RPM,

Angular velocity of cam ω = 

Now time period of the cam in SHM,

T = angle of rise in radian / angular velocity 

T = 1 sec

Key Points

The time period in SHM is simply angle turned upon angular velocity.

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