4 kg of solid material is heated from 15°C to 115°C with the addition of 750 kJ of heat in a furnace. What will be it specific heat?

This question was previously asked in
MPPGCL JE ME 19 March 2019 Official Paper
View all MPPGCL Junior Engineer Papers >
  1. 1.875 kJ/kg °C
  2. 18.75kJ/kg °C
  3. 187.5 kJ/kg °C
  4. 1,875 kJ/kg °C

Answer (Detailed Solution Below)

Option 1 : 1.875 kJ/kg °C
Free
MPPGCL JE Electrical Fundamentals Mock Test
20 Qs. 20 Marks 24 Mins

Detailed Solution

Download Solution PDF

Concept:

The quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree is known as Specific Heat.

Mathematically,

Heat Energy is given by

Q = m c Δ T

where m is mass, c is specific heat and Δ T is temperature difference

Solution:

Heat energy given by the metal piece is 750 kJ

750 = m c ΔT
= 4 × c × (115−15)
750 = 4 × c × 100

∴ c = 1.875 kJ/kg °C

The correct answer is an option (1).

Latest MPPGCL Junior Engineer Updates

Last updated on Jul 18, 2025

-> MPPGCL Junior Engineer Notification 2025 has been released for various fields of post (Advt No. 3233).

-> MPPGCL has announced a total of 90 vacancies for Civil, Mechanical, Electrical, and Electronics Engineering (Junior Engineer).

->  Interested candidates can submit their online application form, from 23rd July to 21st August 2025. 

-> MPPGCL Junior Engineer result PDF has been released at the offiical website.

-> The MPPGCL Junior Engineer Exam Date has been announced.

-> The MPPGCL Junior Engineer Notification was released for 284 vacancies.

-> The selection process includes a Computer Based Test and Document Verification.

-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.

More Specific heat capacity Questions

More Thermal Properties of Matter Questions

Hot Links: teen patti real cash 2024 all teen patti master teen patti classic real cash teen patti