Array MCQ Quiz in తెలుగు - Objective Question with Answer for Array - ముఫ్త్ [PDF] డౌన్‌లోడ్ కరెన్

Answer: Option 4

Explanation: 

Consider the following example 

#include int main() {        int arr[10] = {1, 2, 3, 4, 5, 6, 7};

       arr++;
       return 0;
}

Here arr++; mean that

arr = arr + 1 ;

which is wrong we can not change the base address of an array and it will generate an error.
another way to do that is by using pointers.

#include int main() {        int arr[10] = {1, 2, 3, 4, 5, 6, 7};

       int *p = arr;

       p++;
       return 0;
}

Here int *p = arr; new pointer variable will be created which will start pointing to the first element of the array.

and p++; will cause the pointer to start pointing to the next element of the array.

code:

#include

int main(){

int arr[4][5];

int i, j;

for(i =0; i

for (j =0; j

arr [i][j] = 10 +i + j;

}

}

print("%d", *(arr[1] + 9));

return 0;

}

Key Points

1. C doesn't check array boundaries. A segmentation fault will only occur if you try to dereference a pointer to memory that your program doesn't have permission to access. Simply going past the end of an array is unlikely to cause that behavior. Undefined behavior is just that - undefined. It may appear to work just fine, but you shouldn't be relying on its safety.
2. Your program causes undefined behavior by accessing memory past the end of the array. In this case, it looks like one of your str[i] = c writes overwrite the value in i.

Explanation:

*(arr[1] + 9) can be written as arr[1][9].

as C doesn't follow bound check and follow the row major ordering

arr[1][5] = arr[2][0]  / arr[1][4] will be first row of array and then arr[2][0] will be second row of array 

arr[1][6] = arr[2][1]

arr[1][7] = arr[2][2]

arr[1][8] = arr[2][3]

arr[1][9] = arr[2][4]

arr[2][4] = 10*i + j = 10*2+4 = 24

Option 4 is the answer.

Concept:

An array is a data structure that contains a group of elements. These elements are all of the same data type, such as an integer.

To access element from an array subscript(index) and array name is required

Explanation:

Array name: A

To access 3^rd element in an array A[2] or 2[A] is used.  Therefore Both A[2] and 2[A] represent the value 3

Important point:

A[0] represent the value 1^st element

Where \0 is a null character 

After *p = '0';   \\s1[2] = '0'

100  101 102 103  104

printf(“%s”, s1) will print all starting from address location 100 until the null character.

Output: 1204 

Answer: Option 4

Explanation:

The upper bound:

The largest index is called upper bound of the array.

The lower bound:

The smallest index is called lower bound of the array.

Range of Array:

the range of smallest element to largest index is called range of the array.

Data:

base address = 1100

starting index = 2

index = 125

size of element = 4 word

Formula:

Array index starts with 0:

Address of array location : base address + index × size of data

Array index starts with 2:

Address of array location : base address + (index - 2) ×size of data

Calculation

Address of A[125] = 1100 + (125 - 2) × 4

= 1100 + 123 × 4

= 1592

Concept:

val[2][4] is the two-dimensional array representation with 2 rows and 4 columns

rang of rows : 0 to 1

rand of columns = 0 to 3

Explanation:

Hence the correct answer is Option 4

Key Points 

An array is defined as the collection of similar types of data items stored at contiguous memory locations. Arrays are the derived data type in C programming language which can store the primitive type of data such as int, char, double, float, etc. C array is beneficial if you have to store similar elements. 

Array can be access i th index at array A,

A[ i ]= i [ A ] = *(A+ i) = *(i + A)

Given that,

int array1[ ] = {2, 3);

int array2[ 3 ] = {9};

printf(“%d, %d”, array1[1], 2[array2]);

array1 is dynamic allocation of {2,3}.

array2 is three memory cells and stores 9 at 0th index of array2.

printf(“%d, %d”, array1[1], 2[array2]);

array1[1]= 1st index at array1 = 3

 array2 [2]= 2nd index at array2 = 0

Hence the correct answer is 3, 0.

The correct answer is 490.

Concepts:

Array:

An array is used to store a collection of data, but it is often more useful to think of an array as a collection of variables of the same type.

Explanation:

The given data,

Range of given array: [-10...5,7......15]

A[2][10]= ?

A[-10][7] = 250= starting location = base location of the array.

b= base of the index= starting index.

u= upper of the index= upper index.

r1= (u1-b1+1)= column size= number of rows

r1=(u2-b2+1) =row size= number of columns

Number of rows

r1 =5 – (–10) + 1= 16

Number of columns:

r2= 15 – 7 + 1 = 9

Array size: A_{16 x 9}

Formula:

Row major order:

A[i][j] = base location of the array+ {( i - b1 ) r2 + ( j - b2) } x c

Column major order:

A[i][j] = base location of the array+ {( j - b2 ) r1 + (i - b1) } x c

where is c = count = size of each element.

Calculation:  

column-major order

A[i][j] = base location of the array+ {( j - b2 )r1+ (i-b1) } x c

c = 4

A[2][10] = 250 + {(10 - 7)16 + (2- (- 10)) } x 4

A[2][10] = 250 + {(3)16 +12 } x 4

A[2][10] = 250 + {48 +12 } x 4

A[2][10] = 250 + 240

A[2][10] = 490

Hence the correct answer is 490.

• Basic data type (Primitive Data Structure): Integer, Real, Boolean, Character. Primitive data types are also called simple data types since they cannot be further divided
• Non- primitive data Structure is divided into linear data structure and non-linear data structure


1. Linear data structure: elements(data) form a sequence or a linear list

Examples: Arrays, Linked List, Stacks and Queues

2. Non-Linear data structure: data are not arranged in sequence

Example: Trees, Graphs