Speed Time and Distance MCQ Quiz - Objective Question with Answer for Speed Time and Distance - Download Free PDF
Last updated on Jun 11, 2025
Latest Speed Time and Distance MCQ Objective Questions
Speed Time and Distance Question 1:
A boat covers 64 km in downstream in 4 hours and 48 km in upstream in 6 hours. Find the distance covered by boat in 5 hours still water?
Answer (Detailed Solution Below)
Speed Time and Distance Question 1 Detailed Solution
Given:
Downstream distance = 64 km
Time taken for downstream = 4 hours
Upstream distance = 48 km
Time taken for upstream = 6 hours
Formula used:
Speed = Distance ÷ Time
Speed downstream = (Speed of boat + Speed of current)
Speed upstream = (Speed of boat - Speed of current)
Calculations:
Speed downstream = 64 ÷ 4 = 16 km/hr
Speed upstream = 48 ÷ 6 = 8 km/hr
Let the speed of the boat in still water be 'b' km/hr and the speed of the current be 'c' km/hr.
Speed downstream = b + c = 16
Speed upstream = b - c = 8
Now, solving the equations:
b + c = 16
b - c = 8
Add the two equations:
(b + c) + (b - c) = 16 + 8
2b = 24
b = 12 km/hr
The speed of the boat in still water is 12 km/hr.
Now, the distance covered by the boat in 5 hours in still water is:
Distance = Speed × Time
Distance = 12 × 5 = 60 km
∴ The distance covered by the boat in 5 hours in still water is 60 km.
Speed Time and Distance Question 2:
A bus can cover 320 km distance in 8 hours. If speed of another Bus is 25% more than first bus. Find the time taken by the car to cover 200 km distance?
Answer (Detailed Solution Below)
Speed Time and Distance Question 2 Detailed Solution
Given:
Distance covered by first bus = 320 km
Time taken by first bus = 8 hours
Speed of second bus = 25% more than first bus
Distance to be covered by second bus = 200 km
Formula used:
Speed = Distance / Time
Calculations:
Speed of first bus = 320 km / 8 hours = 40 km/h
Speed of second bus = 40 km/h + 25% of 40 km/h = 40 km/h + 10 km/h = 50 km/h
Time taken by second bus to cover 200 km = Distance / Speed
Time = 200 km / 50 km/h = 4 hours
∴ The time taken by the second bus to cover 200 km is 4 hours.
Speed Time and Distance Question 3:
Train P, which is ‘d’ meters long, takes the same time to pass a 300-meter-long platform as Train Q, which is (d + 200) meters long, takes to pass a 500-meter-long platform. If the ratio of their speeds (Train P to Train Q) is 5:9, then what is the value of d?
Answer (Detailed Solution Below)
Speed Time and Distance Question 3 Detailed Solution
Calculation
Let speed of train P and Q be 5x m/sec. & 9x m/sec. respectively
ATQ,
[ (d+300) / 5x] = [(d+700) / 9x]
So, 9d + 2700 = 5d + 3500
So, 4d = 800
So, d = 200
Speed Time and Distance Question 4:
A boat covers a distance of [3x/5] km downstream and [2x/5] km upstream. The speed of the boat in still water is 12 km/hr, and the speed of the stream is 8 km/hr. It is given that the time taken to travel upstream is 14 hours more than the time taken to travel downstream. What is the total downstream distance travelled by the boat?
Answer (Detailed Solution Below)
Speed Time and Distance Question 4 Detailed Solution
Calculation
Distance travelled by boat in downstream = 3x/5 km
Distance travelled by boat in upstream = [2x / 5] km
ATQ, [2x / 5(12 - 8)] − [3𝑥 / 5(12 + 8)] = 14
Or, [10x−3x] / 100 = 14
So, x = 200
Distance covered in downstream = 200 × [3 / 5] = 120
Speed Time and Distance Question 5:
A train passes a bridge in 18 seconds and a man standing on the bridge in 10 seconds. If the speed of the train is 90 km/hr, what is the length of the bridge ?
Answer (Detailed Solution Below)
Speed Time and Distance Question 5 Detailed Solution
Given:
Speed of the train = 90 km/hr = (90 × 1000) / 3600 = 25 m/s
Time taken to pass the man = 10 seconds
Time taken to pass the bridge = 18 seconds
Formula Used:
Total Length of Train + Length of Bridge = Speed × Time to pass the bridge
Length of Train = Speed × Time to pass the man
Calculation:
Length of Train = Speed × Time to pass the man
⇒ Length of Train = 25 × 10
⇒ Length of Train = 250 m
Total Length of Train + Length of Bridge = Speed × Time to pass the bridge
⇒ 250 + Length of Bridge = 25 × 18
⇒ 250 + Length of Bridge = 450
⇒ Length of Bridge = 450 - 250
⇒ Length of Bridge = 200 m
The length of the bridge is 200 m.
Top Speed Time and Distance MCQ Objective Questions
A train of length 400 m takes 15 seconds to cross a train of length 300 m traveling at 60 km per hour from the opposite direction along a parallel track. What is the speed of the longer train, in km per hour?
Answer (Detailed Solution Below)
Speed Time and Distance Question 6 Detailed Solution
Download Solution PDFGiven
Length of first train (L1) = 400 m
Length of second train (L2) = 300 m
Speed of second train (S2) = 60 km/hr
Time taken to cross each other (T) = 15 s
Concept:
Relative speed when two objects move in opposite directions is the sum of their speeds.
Calculations:
Let the speed of the first train = x km/hr
Total length = 300 + 400
Time = 15 sec
According to the question:
700/15 = (60 + x) × 5/18
28 × 6 = 60 + x
x = 108 km/hr.
Therefore, the speed of the longer train is 108 km per hour.
Running at a speed of 60 km per hour, a train passed through a 1.5 km long tunnel in two minutes, What is the length of the train ?
Answer (Detailed Solution Below)
Speed Time and Distance Question 7 Detailed Solution
Download Solution PDFGiven:
Speed is 60 km per hour,
Train passed through a 1.5 km long tunnel in two minutes
Formula used:
Distance = Speed × Time
Calculation:
Let the length of the train be L
According to the question,
Total distance = 1500 m + L
Speed = 60(5/18)
⇒ 50/3 m/sec
Time = 2 × 60 = 120 sec
⇒ 1500 + L = (50/3)× 120
⇒ L = 2000 - 1500
⇒ L = 500 m
∴ The length of the train is 500 m.
A, B and C run simultaneously, starting from a point, around a circular track of length 1200 m, at respective speeds of 2 m/s, 4 m/s and 6 m/s. A and B run in the same direction, while C runs in the opposite direction to the other two. After how much time will they meet for the first time?
Answer (Detailed Solution Below)
Speed Time and Distance Question 8 Detailed Solution
Download Solution PDFGiven:
Total track length = 1200 m
Speed of A = 2 m/s ; speed of B = 4 m/s
Speed of C = 6 m/s
Formula used:
Distance = relative speed × time
Calculation:
Relative speed of A and B = (4 - 2) = 2 m/s
Relative speed of B and C = (6 + 4) = 10 m/s
Relative speed of A and C = (6 + 2) = 8 m/s
Time taken by A and B = 1200/2 = 600 sec
Time taken by B and C = 1200/10 = 120 sec
Time taken by A and C = 1200/8 = 150 sec
A, B and C will meet at = L.C.M {600,120, 150} = 600 sec = 600/60 = 10 minutes
∴ The correct answer is 10 minutes.
A man travels from A to B at a speed of 36 km/hr in 74 minutes and he travels a distance from B to C with a speed of 45 km/hr in 111 minutes. Find the average speed of whole journey.
Answer (Detailed Solution Below)
Speed Time and Distance Question 9 Detailed Solution
Download Solution PDFGiven:
A man travels from A to B at a speed of 36 km/hr in 74 minutes and he travels a distance from B to C with a speed of 45 km/hr in 111 minutes.
Formula used:
Average speed = Total distance/Total time taken
Calculation:
Time taken = 74 min : 111 min [given]
Ratio of Time taken = 2 : 3
Average Speed =
Average Speed = 207/5
Average Speed = 41.4 km/hr
∴ The average speed of whole journey is 41.4 km/h
A thief committed a crime and escaped from the spot at a speed of 12 m/h. A Security guard started chasing him 20 minutes after the thief started running and caught him in the next 20 minutes. What is the speed (in m/h) of the Security guard?
Answer (Detailed Solution Below)
Speed Time and Distance Question 10 Detailed Solution
Download Solution PDFConcept used:
Speed × time = distance
Calculation:
In the 1st 20 min the thief cover distance = 4 m,
20 min in hour = 20/60 hour
Let's assume that the speed of security guard = x m/hr, where x > 12
According to the question,
⇒ (x - 12) × 20/60 = 4
⇒ x - 12 = 12
⇒ x = 24
∴ The correct answer is 24 m/h
In a 1500 m race, Anil beats Bakul by 150 m and in the same race Bakul beats Charles by 75 m. By what distance does Anil beat Charles?
Answer (Detailed Solution Below)
Speed Time and Distance Question 11 Detailed Solution
Download Solution PDFGiven:
In a 1500 m race, Anil beats Bakul by 150 m and in the same race Bakul beats Charles by 75 m.
Concept used:
Time × Speed = Distance
Calculation:
According to the question,
Anil goes 1500m while Bakul goes (1500 - 150) i.e. 1350m.
Ratio of speed of Anil and Bakul = 1500 : 1350 = 10 : 9 = 200 : 180
According to the question,
Bakul goes 1500m while Charlie goes (1500 - 75) i.e. 1425m.
Ratio of speed of Bakul and Charlie = 1500 : 1425 = 20 : 19 = 180 : 171
So, the ratio of the speeds of Anil, Bakul and Charlie = 200 : 180 : 171
Let the speeds of Anil, Bakul and Charlie be 200k, 180k and 171k m/s respectively.
Time taken by Anil to finish the race = 1500/200k = 7.5/k seconds
Now, Anil beats Charlie by = (200 - 171)k ×7.5/k = 217.5m
∴ Anil beat Charlie by 217.5m.
Shortcut Trick
In a 1500 m race, Anil beats Bakul by 150 m
When Anil completes the race, Bakul covered (1500 - 150) = 1350 m
In a 1500 m race Charles is 75 m behind Bakul
So, in 1350 m race Charles is 75/1500 × 1350 = 67.5 m behind Bakul
So, Charles is (67.5 + 150) = 217.5 m behind from Anil in 1500 m race
∴ Anil beat Charlie by 217.5m.
Geeta runs 5/2 times as fast as Babita. In a race, if Geeta gives a lead of 40 m to Babita, find the distance from the starting point where both of them will meet (correct up to two decimal places).
Answer (Detailed Solution Below)
Speed Time and Distance Question 12 Detailed Solution
Download Solution PDFGiven:
Geeta runs 5/2 times as fast as Babita
Geeta gives a lead of 40 m to Babita
Formula Used:
Distance = Speed × Time
Calculation:
Let the speed of Babita be 2x
⇒ Speed of Geeta = (5/2) × 2x = 5x
Let the distance covered by Geeta be y meters
⇒ Distance covered by Babita = (y - 40) meters
As time is constant, distance is directly proportional to speed
⇒
⇒ 2y = 5y - 200
⇒ y = 200/3 = 66.67m
∴ The distance from the starting point where both of them will meet is 66.67 m
A boat goes 20 km upstream and 44 km downstream in 8 hours. In 5 hours, it goes 15 km upstream and 22 km downstream. Determine the speed of the boat in still water.
Answer (Detailed Solution Below)
Speed Time and Distance Question 13 Detailed Solution
Download Solution PDFConcept used:
If upstream speed = U and downstream speed = D, then speed of boat = (U + D)/2
Calculation:
According to the question,
20/U + 44/D = 8 … (i)
15/U + 22/D = 5 … (ii)
Multiply by 2 the equation (ii) then subtract from 1 we get
20/U + 44/D = 8
30/U + 44/D = 10
- 10/U = - 2
⇒ U = 5 km/hr
Putting the value in equation (i), we get D = 11
So, the speed of boat = (U + D)/2 = (5 + 11)/2 = 8 km/hr
∴ The correct answer is 8 km/hr
Two trains start at the same time from Bangalore and Chennai and proceed towards each other at the speeds of 80 km/h and 95 km/h. When they meet, it is found that one train has travelled 180 km more than the other. The distance between Bangalore and Chennai is:
Answer (Detailed Solution Below)
Speed Time and Distance Question 14 Detailed Solution
Download Solution PDFGiven:
Speed of train 1 = 80 km/h
Speed of train 2 = 95 km/h
Difference in distance = 180 km
Concept:
Distance = Speed × Time
Solution:
Let the time of travelling be 't' hours
Distance travelled by train with speed 80 km/h = 80 × t
Distance travelled by train with speed 95 km/h = 95 × t
According to the question,
Difference in distance travelled by two train = 180 km
⇒ 95 t - 80t = 180
⇒ 15t = 180
⇒ t = 12 hours
Distance between stations = 80 × 12 + 95 × 12 = 960 + 1140 = 2100km
Hence, the distance between Bangalore and Chennai is 2100 km .
Two trains, one 152.5 m long and the other 157.5 m long, coming from opposite directions crossed each other in 9.3 seconds. The combined speed of the two trains every hour would then be:
Answer (Detailed Solution Below)
Speed Time and Distance Question 15 Detailed Solution
Download Solution PDFGiven:-
Train1= 152.5m
Train2= 157.5m
Time = 9.3 sec
Calculation:-
⇒ Total distance to be covered = total length of both the trains
= 152. 5 + 157.5
= 310 m
Total time taken = 9.3 sec
Speed = distance/time
= (310/9.3) m/sec
= (310/9.3) × (18/5)
= 120 km/hr
∴ The combined speed of the two trains every hour would then be 120 km/hr.
Alternate Method When two trains are moving in opposite direction-
Let the speed of ine is 'v' and the second is 'u'
∴ Combined speed = v + u
Total distance = 152.5 + 157.5
= 310 m
∴ Combined speed = Total distance/total time
⇒ (v + u) = 310/9.3
⇒ (v + u) = 33.33 m/s
⇒ (v + u) = 33.33 × (18/5)
⇒ (v + u) = 120 km/hr