Simplification MCQ Quiz - Objective Question with Answer for Simplification - Download Free PDF

Calculation:

⇒ 

⇒ 

⇒ 

⇒ 

⇒ 

⇒ 

⇒ 4

Given:

1980 ÷ 9 + [-77 + {-1980 + (1/4 of 7920)}]

Concept used:

BODMAS rule

Calculations:

1980 ÷ 9 + [-77 + {-1980 + (1/4 × 7920)}]

⇒ 1980 ÷ 9 + [-77 + {-1980 + (7920/4)}]

⇒ 1980 ÷ 9+ [-77 + {-1980 + (1980)}]

⇒ 1980 ÷ 9+ [-77 + {-1980 + 1980}]

⇒ 1980 ÷ 9 + [-77 + {0}]

⇒ 220 + [-77]

⇒ 220 - 77 = 143

∴ The simplified value of the equation is 143.

Formula used:

(a3 - b3)/ (a2 + ab + b2) = (a - b) (a² + ab + b²) / (a2 + ab + b2) 

Calculation:

Let the 0.53 be "a" and 0.12 be "b" .

(a³ - b³)/ (a² + ab + b²) = (a - b) (a2 + ab + b2) / (a2 + ab + b2) 

According to the above formula,

Simplify by Canceling the Common Factor:

Cancel the Common Terms:

Since a2 + ab + b2 is common in both the numerator and the denominator, they cancel each other out:

⇒ (a - b) (a2 + ab + b2) / (a2 + ab + b2) = (a - b)

⇒ 0.53  - 0.12 = 0.41

∴ The correct answer is 0.41

Given:

44 ÷ 11 × 4 + 5 × 8 ÷ 4 - 7 × 36 ÷ 14 + 7 × 4

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:

44 ÷ 11 × 4 + 5 × 8 ÷ 4 - 7 × 36 ÷ 14 + 7 × 4

⇒ 4 × 4 + 5 × 2 - 18 + 7 × 4

⇒ 16 + 10 - 18 + 28

⇒ 54 - 18

⇒ 36

∴ The value is 36.

Given:

5 × 2 + (3.5 - 1.5) of (3 - 3)

Calculation:

5 × 2 + (3.5 - 1.5) of (3 - 3)

⇒ 5 × 2 + (3.5 - 1.5) of 0

⇒ 5 × 2 + 2 × 0

⇒ 10

∴ The result is: 10

Concebt used

a.b̅ = a.bbbbbb

a.0b̅ = a.0bbbb

Calculation

0.7 = 0.700000 ̇....

Now, 0.7777…  or  is largest among all.

Solution:

= 25/2 + 37/3 + 73/6

= (75 + 74 + 73)/6

= 222/6

= 37

Shortcut Trick

= 12 + 12 + 12 + (1/2 + 1/3 + 1/6)

= 36 + 1 = 37

Solution:

We have to follow the BODMAS rule

Calculation:

⇒ ? = 3²

∴ ? = 9

Formula used:

(a + b)² = a² + b² + 2ab

Calculation:

Given expression is:

⇒  

⇒  

⇒  

⇒  

Since,

a2 - b2 = (a - b) ( a + b)

⇒ 0.9 × 0.7 = 0.63

∴ Answer is 0.63

Concept:

We can find √x using the factorisation method.

Calculation:

√[(10 + √25) (12 - √49)]

⇒ √[(10 + 5)(12 – 7)]

⇒ √(15 × 5)

⇒ √(3 × 5 × 5)

⇒ 5√3

Given,

2³ × 3⁴ × 1080 ÷ 15 = 6^x

⇒ 2³ × 3⁴ × 72 = 6^x

⇒ 2³ × 3⁴ × (2 × 6²) = 6^x

⇒ 2⁴ × 3⁴ × 6² = 6^x

⇒ (2 × 3)⁴ × 6² = 6^x           [∵ x^m × y^m = (xy)^m]

⇒ 6⁴ × 6² = 6^x

⇒ 6^{(4 + 2)} = 6^x

⇒ x = 6

Given:

√3n = 729

Formulas used:

(x^a)^b = x^ab

If x^a = x^b then a = b 

Calculation:

√3n = 729

⇒ √3n = (3²)³

⇒ (3n)^1/2 = (32)3

⇒ (3n)1/2 = 3⁶

⇒ n/2 = 6 

∴  n = 12 

Given expression,

(81.84 + 118.16) ÷ 5³ = 1.2 × 2 + ?

⇒ 200 ÷ 5³ = 1.2 × 2 + ?

⇒ 200 ÷ 125 = 1.2 × 2 +?

⇒ 1.6 = 2.4 + ?

⇒ ? = -0.8