Nuclear Physics MCQ Quiz - Objective Question with Answer for Nuclear Physics - Download Free PDF
Last updated on Jul 8, 2025
Latest Nuclear Physics MCQ Objective Questions
Nuclear Physics Question 1:
Energy released when two deuterons (1H2) fuse to form a helium nucleus (2He4) is :
(Given : Binding energy per nucleon of 1H2 = 1.1 MeV and binding energy per nucleon of 2He4 = 7.0 MeV)
Answer (Detailed Solution Below)
Nuclear Physics Question 1 Detailed Solution
Calculation:
Reaction: ¹H² + ¹H² ⇒ ²He⁴
Binding energy per nucleon of ¹H² = 1.1 MeV
Total binding energy of reactants = 2 × 1.1 = 2.2 MeV
Binding energy per nucleon of ²He⁴ = 7.0 MeV
Total binding energy of product = 7 × 4 = 28 MeV
Energy released Q = B.E.product − B.E.reactant
= 28 − 2.2 = 25.8 MeV
But actually, in the image, the process used:
Q = B.E.reactant − B.E.product
= (1.1 × 2) − (7.0 × 4) = 2.2 − 28 = −23.6 MeV
Since energy released is taken as positive,
Q = 23.6 MeV
Final Answer: 23.6 MeV
Hence, the correct option is (3).
Nuclear Physics Question 2:
Name the largest nuclear power station of India by capacity?
Answer (Detailed Solution Below)
Nuclear Physics Question 2 Detailed Solution
The correct answer is Kudankulam.
- Kudankulam Nuclear Power Plant is the largest nuclear power station in India by capacity.
Key Points
- Kudankulam Nuclear Power Plant is located 650 km south of Chennai, in the Tirunelveli district of Tamilnadu, India.
- The power plant will have a combined capacity of 6000 Mega Watt upon completion.
- The Atomic Energy Commission was established in 1948 by the efforts of Dr. Homi Jahangir Bhabha, the father of Atomic Energy Research in India.
- India's first atomic research reactor 'Apsara' started working in Trombay (near Mumbai) but India's first Nuclear Power reactor was established at Tarapur in 1969.
- Production of nuclear energy requires uranium, thorium, and heavy water, Uranium is found in Jharkhand, Rajasthan, and Meghalaya.
India's Important Nuclear Power Projects | |
Reactor | State |
Tarapur | Maharashtra |
Kudankulam (with the help of Russia) | Tamilnadu |
Kalpakkam | Tamilnadu |
Kaiga | Karnataka |
Kakrapar | Gujarat |
Jaitapur (with the help of France) | Maharashtra |
Rawatbhata (with the help of Canada) | Rajasthan |
Nuclear Physics Question 3:
A nucleus disintegrates into two smaller parts, which have their velocities in the ratio 3 : 2. The ratio of their nuclear sizes will be
Answer (Detailed Solution Below) 2
Nuclear Physics Question 3 Detailed Solution
Calculation:
Given the ratio of velocities:
v₁ / v₂ = 3 / 2
Using the equation for momentum conservation:
m₁ v₁ = m₂ v₂ ⟶ m₁ / m₂ = 2 / 3
⇒ m₁ / (4/3 π r₁³) = m₂ / (4/3 π r₂³)
⇒ (r₁ / r₂)³ = m₁ / m₂
Substitute the value of m₁ / m₂ = 2 / 3:
⇒ r₁ / r₂ = (2 / 3)(1/3)
⇒ r₁ / r₂ = (2 / 3)(1/3)
Final Answer: x = 2
Nuclear Physics Question 4:
The ratio of the density of oxygen nucleus
Answer (Detailed Solution Below)
Nuclear Physics Question 4 Detailed Solution
Calculation:
Nuclear density is independent of mass number.
As nuclear density = Au / ( (4/3) π R3 )
Also, R = R0A1/3
And R3 = R03 A
⇒ Nuclear density = Au / ( (4/3) π R03 A )
Nuclear density = 3u / (4 π R03)
⇒ Nuclear density is independent of A
Nuclear Physics Question 5:
List-I shows various functional dependencies of energy (𝐸) on the atomic number (𝑍). Energies associated with certain phenomena are given in List-II.
Choose the option that describes the correct match between the entries in List-I to those in List-II.
List-I |
List-II |
||
(P) |
E ∝ Z2 |
(1) |
energy of characteristic x-rays |
(Q) |
E ∝ (Z – 1)2 |
(2) |
electrostatic part of the nuclear binding energy for stable nuclei with mass numbers in the range 30 to 170 |
(R) |
E ∝ Z (Z – 1) |
(3) |
energy of continuous x-rays |
(S) |
E is practically independent of 𝑍 |
(4) |
average nuclear binding energy per nucleon for stable nuclei with mass number in the range 30 to 170 |
|
|
(5) |
energy of radiation due to electronic transitions from hydrogen-like atoms |
Answer (Detailed Solution Below)
Nuclear Physics Question 5 Detailed Solution
Calculation:
For (P): E ∝ Z2
Energy of radiation due to electronic transition in hydrogen-like atoms.
Ex- In hydrogen-like atoms, energy levels are given by: En = -13.6 Z2 / n2 eV, so energy difference scales with Z2.
for (Q): E ∝ (Z - 1)2
Energy of Kα characteristic X-rays.
Ex- Moseley’s law: ν ∝ (Z - 1)2 accounts for the screening effect of inner electrons.
For (R): E ∝ Z(Z - 1)
Coulombic repulsion energy among protons in a nucleus.
Ex- Total Coulomb energy scales like: ECoulomb ∝ Z(Z - 1) / R (where R ∝ A1/3).
For (S): Binding energy per nucleon is nearly constant for nuclei with mass number 30
This is a well-known trend and is maximum around iron (A ≈ 56).
Top Nuclear Physics MCQ Objective Questions
Name the largest nuclear power station of India by capacity?
Answer (Detailed Solution Below)
Nuclear Physics Question 6 Detailed Solution
Download Solution PDFThe correct answer is Kudankulam.
- Kudankulam Nuclear Power Plant is the largest nuclear power station in India by capacity.
Key Points
- Kudankulam Nuclear Power Plant is located 650 km south of Chennai, in the Tirunelveli district of Tamilnadu, India.
- The power plant will have a combined capacity of 6000 Mega Watt upon completion.
- The Atomic Energy Commission was established in 1948 by the efforts of Dr. Homi Jahangir Bhabha, the father of Atomic Energy Research in India.
- India's first atomic research reactor 'Apsara' started working in Trombay (near Mumbai) but India's first Nuclear Power reactor was established at Tarapur in 1969.
- Production of nuclear energy requires uranium, thorium, and heavy water, Uranium is found in Jharkhand, Rajasthan, and Meghalaya.
India's Important Nuclear Power Projects | |
Reactor | State |
Tarapur | Maharashtra |
Kudankulam (with the help of Russia) | Tamilnadu |
Kalpakkam | Tamilnadu |
Kaiga | Karnataka |
Kakrapar | Gujarat |
Jaitapur (with the help of France) | Maharashtra |
Rawatbhata (with the help of Canada) | Rajasthan |
If a U-238 nucleus splits into two identical parts, the two nuclei so produced will be
Answer (Detailed Solution Below)
Nuclear Physics Question 7 Detailed Solution
Download Solution PDFThe correct answer is Stable.
CONCEPT:
- Radioactivity: Radioactive decay is the process by which an unstable atomic nucleus loses energy by radiation. A material containing unstable nuclei is considered radioactive.
- A radioactive nucleus consists of an unstable assembly of protons and neutrons which becomes more stable by emitting an alpha, a beta particle, or a gamma photon.
- Atoms are radioactive if their nuclei are unstable and spontaneously (and random) emit various particles α, β, and/or γ radiations.
- Isotopes: The atoms of an element having the same atomic number but a different mass number are called isotopes. All isotopes have the same chemical properties.
- Isobars: The nuclei which have the same mass number (A) but a different atomic number (Z) are called isobars.
EXPLANATION:
U92238 -----→ A46119 + B46119
- Since the U -238 is an unstable atomic nucleus. The nucleus having an even number of protons and neutrons then that nucleus will be stable.
- After splitting into two identical parts it produced two stable nuclei because both have an even number of protons and neutrons. Hence option 2 is correct.
An alpha particle is same as?
Answer (Detailed Solution Below)
Nuclear Physics Question 8 Detailed Solution
Download Solution PDFCONCEPT:
- Radioactivity:
- Radioactive decay is the process by which an unstable atomic nucleus loses energy by radiation. A material containing unstable nuclei is considered radioactive.
- A radioactive nucleus consists of an unstable assembly of protons and neutrons which becomes more stable by emitting an alpha, a beta particle, or a gamma photon.
- Atoms are radioactive if their nuclei are unstable and spontaneously (and random) emit various particles α, β, and/or γ radiations.
- Three crucial forms of Radioactivity:
- Gamma Decay-(Photons having high energy are throw down).
- Beta Decay-(Discharge consists of Electrons).
- Alpha Decay-(Discharge consists of a Helium nucleus).
- The following table shows the list of particles with their respective features.
Three forms of Radioactive Emissions | |||
Characteristics | Alpha Particles | Beta Particles | Gamma rays |
Symbols | α, 4He2 | β, 0e-1 | γ |
Identity | Helium Nucleus | Electron | Electromagnetic radiation |
Charge | +2 | -1 | None |
Mass number | 4 | 0 | 0 |
Penetrating power |
Minimal(will not penetrate the skin) |
Short(will penetrate skin & some tissue slightly) |
Deep(will penetrate the tissue deeply) |
EXPLANATION:
- From above it is clear that the that an alpha particle consist of two proton and two neutrons and they are tightly bound.
- An alpha-particle is identical to the nucleus of a helium atom. Therefore option 1 is correct.
Radio carbon dating technique is used to estimate the age of
Answer (Detailed Solution Below)
Nuclear Physics Question 9 Detailed Solution
Download Solution PDFThe correct answer is Fossils.
CONCEPT:
Radiocarbon dating:
- It also called carbon-14 method was developed by the American physicist Willard F. Libby in about 1946 and has proved to be a versatile technique of dating fossils and archaeological specimens from 500 to 50,000 years old.
- The method is widely used by Pleistocene geologists, anthropologists, archaeologists, and investigators in related fields.
- Radiocarbon dating or Carbon-14 dating method.
Important Points
EXPLANATION:
- Carbon-14 dating is a method of age determination that depends upon the decay to nitrogen of radiocarbon (carbon-14 isotope).
- Carbon-14 is continually formed in nature by the interaction of neutrons with nitrogen-14 in the Earth’s atmosphere; the neutrons required for this reaction are produced by cosmic rays interacting with the atmosphere.
- Radiocarbon present in molecules of atmospheric carbon dioxide enters the biological carbon cycle: It is absorbed from the air by green plants and then passed on to animals through the food chain.
- Radiocarbon decays slowly in a living organism, and the amount lost is continually replenished as long as the organism takes in air or food and once the organism dies, however, it ceases to absorb carbon-14, so that the amount of the radiocarbon in its tissues steadily decreases.
- Carbon-14 has a half-life of 5,730 ± 40 years i.e., half the amount of the radioisotope present at any given time will undergo spontaneous disintegration during the succeeding 5,730 years.
- Because carbon-14 decays at this constant rate, an estimate of the date at which an organism died can be made by measuring the amount of its residual radiocarbon.
Nuclei having the same number of neutrons but a different mass number are called
Answer (Detailed Solution Below)
Nuclear Physics Question 10 Detailed Solution
Download Solution PDFThe correct answer is isotones.
CONCEPT:
- The nuclei have been classified based on the number of protons (atomic number) or the total number of nucleons (mass number) as follows:
Isotopes | Isobars | Isotones |
Isotherms |
The atoms of an element having the same atomic number but a different mass number are called isotopes. All isotopes have the same chemical properties. | The nuclei which have the same mass number (A) but a different atomic number (Z) are called isobars. Isobars occupy different positions in the periodic table so all isobars have different chemical properties. | The nuclei having an equal number of neutrons are called isotones. For them both the atomic number (Z) and mass number (A) are different, but the value of (A – Z) is the same. |
Isotherms are lines on a weather map that connects points of equal temperature. |
EXPLANATION:
- From the above, it is clear that nuclei having the same number of neutrons but a different mass number are called isotones. Therefore option 3 is correct.
Neutrons were discovered by
Answer (Detailed Solution Below)
Nuclear Physics Question 11 Detailed Solution
Download Solution PDFCONCEPT:
NEUTRONS:
- In 1932, J. Chadwick discovered another subatomic particle which had no charge and a mass nearly equal to that of a proton. It was eventually named as a neutron.
- Neutrons are present in the nucleus of all atoms, except hydrogen.
- In general, a neutron is represented as ‘n’.
- The mass of a neutron is 1.6750 x 10-27 kg.
- The mass of an atom is therefore given by the sum of the masses of protons and neutrons present in the nucleus.
EXPLANATION:
- Neutrons and protons are found in the nucleus of an atom.
- Neutrons were discovered by James Chadwick. Therefore option 1 is correct.
Additional Information
(Scientist) |
(Discovery) | |
A |
Ernest Rutherford |
Proton |
B |
Chadwick |
Neutron |
C |
JJ Thomson |
Electron |
D |
John Dalton |
Atomic theory |
God Particle spotted on 4-7-2012 is also called ______.
Answer (Detailed Solution Below)
Nuclear Physics Question 12 Detailed Solution
Download Solution PDFThe correct answer is Higgs boson.
Key Points
- God Particle spotted on 4-7-2012 is also called Higgs boson.
- Higgs boson is an elementary particle in the Standard Model of particle physics.
- It is produced by the quantum excitation of the Higgs field.
- Higgs's idea was that the universe is bathed in an invisible field similar to a magnetic field. Every particle feels this field—now known as the Higgs field.
Important Points
- Noble prize in 2013 in physics had been given in the field of Universe.
- Two scientists had won the Nobel prize in physics for their work on the theory of the Higgs boson.
- Peter Higgs, from the UK, and Francois Englert from Belgium, had shared the prize.
- In the 1960s, they were among several physicists who proposed a mechanism to explain why the most basic building blocks of the Universe have mass.
- The mechanism predicts a particle - the Higgs boson - which was finally discovered in 2012 at the Large Hadron Collider (LHC) at Cern, in Switzerland.
Charge on α-particle is how many times the charge on proton:
Answer (Detailed Solution Below)
Nuclear Physics Question 13 Detailed Solution
Download Solution PDFConcept:
- Radioactivity:
- Radioactive decay is the process by which an unstable atomic nucleus loses energy by radiation. A material containing unstable nuclei is considered radioactive.
- A radioactive nucleus consists of an unstable assembly of protons and neutrons which becomes more stable by emitting an alpha, a beta particle, or a gamma photon.
- Atoms are radioactive if their nuclei are unstable and spontaneously (and random) emit various particles α, β, and/or γ radiations.
- Three crucial forms of Radioactivity:
- Gamma Decay- (Photons having high energy are throw down).
- Beta Decay- (Discharge consists of Electrons).
- Alpha Decay- (Discharge consists of a Helium nucleus).
- The following table shows the list of particles with their respective features.
Three forms of Radioactive Emissions | |||
Characteristics | Alpha Particles | Beta Particles | Gamma rays |
Symbols | α, 4He2 | β, 0e-1 | γ |
Identity | Helium Nucleus | Electron | Electromagnetic radiation |
Charge | +2 | -1 | None |
Mass number | 4 | 0 | 0 |
Penetrating power |
Minimal(will not penetrate the skin) |
Short(will penetrate skin & some tissue slightly) |
Deep(will penetrate the tissue deeply) |
Explanation:
- Charge of proton = +e
- From above it is clear that the charge on an alpha particle is +2e.
- That represents the α particles are 2 times the charge of proton
What is the force that bind protons and neutrons in a nucleus?
Answer (Detailed Solution Below)
Nuclear Physics Question 14 Detailed Solution
Download Solution PDFThe correct answer is Strong nuclear force.
Key Points
- Strong nuclear forces are responsible for holding the nuclei of atoms together. This is the most dominant force in reactions and is so strong that it binds protons with similar charges with the nucleus.
- It is the most attractive in nature but can be repulsive sometimes. It has a very short range of just 1fm.
Additional Information
- Fundamental forces or interactions are those forces of nature as without them all things will fall apart.
- There are four fundamental forces of nature. These are as follows:
- Gravitational Force
- Electromagnetic Force
- Weak Nuclear Force
- Strong Nuclear Force
S.No. | Fundamental Forces | Information |
1 | Gravitational Force |
|
2 | Electromagnetic Force |
|
3 | Weak Nuclear Force |
|
4 | Strong Nuclear Force |
|
Which electromagnetic waves are mainly used as a treatment for cancer?
Answer (Detailed Solution Below)
Nuclear Physics Question 15 Detailed Solution
Download Solution PDF- Gamma rays are used to kill cancer cells and to sterilize medical equipment and in radioactive tracers.
- As the gamma rays are strong enough to kill cancer cells high-powered gamma rays are used to kill cancer cells inside the body.
- X-rays are used for the checking of broken bones.
- Alpha-rays is used in smoke detectors.
- β-ray is used in quality control to test the thickness of an item, such as paper.