Clock and Calendar MCQ Quiz - Objective Question with Answer for Clock and Calendar - Download Free PDF

Last updated on May 24, 2025

Data Sufficiency is a technique for evaluating if the information provided is adequate to respond to the query. Questions about data sufficiency may involve coding-decoding, blood relations, direction sense tests, etc. difficulties. A calendar is a well-ordered list of days, weeks, and months in a specific period of time. Finding the date, the month, the week, and other information from various statements in the exam is one of the most crucial topics in the government sector. In order to reach the right conclusion, the data sufficiency calendar question provided two statements, 1 and 2. with an appropriate check of the assertion. The data sufficiency calendars-based question requires us to first carefully read both statements, determine whether the first statement is enough to complete an answer, if not, then examine the second statement, and note what the question is actually asking. There may be instances where we need to use both statements to provide the requested response.

Latest Clock and Calendar MCQ Objective Questions

Clock and Calendar Question 1:

The question given below, two statements I & II have been given. Analyze and answer whether the data provided in the two statements are sufficient to answer the question or not.

It is 7:00 pm, when can Dipali get the next bus from Noida to Delhi?

I. Buses for Delhi leave after every 30 minutes, until 11 pm.
II. 20 minutes ago, a bus has left for Delhi.

  1. Statement I alone is sufficient, but statement II alone is not sufficient
  2. Statement II alone is sufficient, but statement I alone is not sufficient
  3. Data in both the statements together are not sufficient,
  4. Both statement I and statement II together are needed,

Answer (Detailed Solution Below)

Option 4 : Both statement I and statement II together are needed,

Clock and Calendar Question 1 Detailed Solution

According to the question,

Statement I: Buses for Delhi leave after every 30 minutes, until 11 pm.

Here, no information regarding last bus timing from Noida is given, therefore statement I alone is not sufficient to answer the question.

Statement II: 20 minutes ago, a bus has left for Delhi.

Here, last bus timing is 6:40 pm (7:00 pm - 20 min) for Delhi but frequency of the bus cannot be determined, therefore statement I alone is not sufficient to answer the question.

Combining statement I and II: Buses for Delhi leave after every 30 minutes, until 11 pm. 20 minutes ago, a bus has left for Delhi.

Last bus timing from Noida was 6:40 pm and as buses leave after every 30 minute. Thus the next bus would be at 7:10 pm (6:40 pm + 30 min).

 Both statement I and statement II together are needed to answer the question.

Hence, "Option 4" is the correct answer.

Clock and Calendar Question 2:

"In the below given question, a few statements have been given. Analyse the given statements and answer whether the data given in the statements are sufficient to answer the question or not.

I. Buses for Ramnagar leave after every 30 minutes, till 10 p.m.
II. Fifteen minutes ago, one bus has left for Ramnagar.
It is 8:00 p.m., when can Hemant get ne×t bus for Ramnagar from Dhanpur?"

  1. the data in statement I alone are sufficient to answer the question
  2. if the data in statement II alone are sufficient to answer the question
  3. if the data even in both the statement together are not sufficient to answer the question
  4. if the data in both the statements together are needed

Answer (Detailed Solution Below)

Option 4 : if the data in both the statements together are needed

Clock and Calendar Question 2 Detailed Solution

According to the question,

Statement I: Buses for Ramnagar leave after every 30 minutes, till 10 p.m.

Here, no information regarding last bus timing from Ramnagar is given, therefore statement I alone is not sufficient to answer the question.

Statement II: Fifteen minutes ago, one bus has left for Ramnagar.

Here, last bus timing is 7:45 pm (8:00 pm - 15 min) for Ramnagar but frequency of the bus cannot be determined, therefore statement I alone is not sufficient to answer the question.

Combining statement I and II: Buses for Ramnagar leave after every 30 minutes, till 10 p.m. Fifteen minutes ago, one bus has left for Ramnagar.

Last bus timing from Ramnagar was 7:45 pm and as buses leave after every 30 minute. Thus the ne×t bus would be at 8:45 pm (6:40 pm + 30 min). It is mentioned that buses leave till 10:00 pm, therefore Hemant can get ne×t bus for Ramnagar from Dhanpur.

 Both statement I and statement II together are needed to answer the question.

Hence, "Option 4" is the correct answer.

Clock and Calendar Question 3:

In the below given question, a few statements have been given. Analyze the given statements and answer whether the data given in the statements are sufficient to answer the question or not.
I. The last day of the month is a Wednesday.
II. The third Saturday of the month was seventeenth.
What day is the fourteenth of a given month?

  1. if the data in statement I alone are sufficient to answer the question
  2. if the data in statement II alone are sufficient to answer the question
  3. if the data even in both the statement together are not suffecient to answer the question
  4. if the data in both the statements together are needed

Answer (Detailed Solution Below)

Option 2 : if the data in statement II alone are sufficient to answer the question

Clock and Calendar Question 3 Detailed Solution

According to the given question, we need to find the day of the 14th of the given month.

Statement 1: The last day of the month is a Wednesday.

If the last day is Wednesday we are not able to find a day on the 14th of that month because we don't know whether the month is of 28 days or 29 days or 30 days or 31 days.

Therefore, Statement-1 alone is not sufficient to answer the question.

Statement 2: The third Saturday of the month was seventeenth.

If the 17th day of the given month is Saturday then we can easily find the 14th day by subtracting 3 odd days from Saturday i.e., (6 - 3) = 3. means Wednesday.

Therefore, Statement-2 alone is sufficient to answer the question.

Hence, "Option 2" is the correct answer.

Additional InformationHere we use odd days as: Sunday = 0 , Monday = 1, Tuesday = 2, Wednesday = 3, Thursday = 4, Friday = 5, and Saturday = 6.  

Clock and Calendar Question 4:

If the 14th September of an year is a Tuesday, then which day of the week will the 17th October of the same year be?

  1. Thursday
  2. Saturday
  3. Sunday
  4. Monday

Answer (Detailed Solution Below)

Option 3 : Sunday

Clock and Calendar Question 4 Detailed Solution

From 14th September to 17th October:

Days left in September:

September has 30 days, so days remaining after the 14th = 30 - 14 = 16 days.

Days in October before the 17th:

Days = 17 days.

Total days between the two dates:

Total = 16 (September) + 17 (October) = 33 days.

Calculate the day of the week:

33 days modulo 7 gives us the remainder when divided by 7:

33 ÷ 7 = 5

32 ÷ 7 = 4 remainders 5

Starting from Tuesday (14th September):

Counting 5 days from Tuesday:

Tuesday → Wednesday (1) → Thursday (2) → Friday (3) → Saturday (4) Sunday(5)

Thus, 17th October will be a Sunday.

Hence the correct answer is, Option(3)

Clock and Calendar Question 5:

Which of the following is a leap year?

  1. 1600
  2. 2000
  3. 2400
  4. All options are correct

Answer (Detailed Solution Below)

Option 4 : All options are correct

Clock and Calendar Question 5 Detailed Solution

To determine if a particular year is a leap year, we can follow these rules:

  1. A year is a leap year if it is divisible by 4.
  2. However, if the year is divisible by 100, it is not a leap year, unless:
  3. The year is also divisible by 400, in which case it is a leap year.

Now, let's check each option,

1) 1600: It is a leap year because it is divisible by 400.

2) 2000It is a leap year because it is divisible by 400.

3) 2400: It is a leap year because it is divisible by 400.

Hence, the correct answer is "All options are correct".

Top Clock and Calendar MCQ Objective Questions

You are given a question and two statements I and II. You have to decide whether the data provided in the statements are sufficient to answer the question.

On which date of month was Harish born in February 2000?

Statements:

I. Harish was born on an even date of the month.

II. Harish’s birth date was a prime number.

  1. Data in both statements I and II together are necessary to answer the question
  2. Data in statement I alone is sufficient to answer the question
  3. Data in both statements I and II together are not sufficient to answer the question
  4. Data in statement II alone is sufficient to answer the question

Answer (Detailed Solution Below)

Option 1 : Data in both statements I and II together are necessary to answer the question

Clock and Calendar Question 6 Detailed Solution

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Statements:

I. Harish was born on an even date of the month → 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28

II. Harish’s birth date was a prime number → 2, 3, 5, 7, 11, 13, 17, 19, 23, 29

But we know that 2 is the smallest even prime number.

According to both statements we can say that on 2nd February 2000 Harish was born.

Hence, Option (1) is correct.

The dates 3rd April, 2005; 6th August, 2010 and 5th December, 2013 when written in Date-Month-Year Form have a unique mathematical property. The Indian Independence Day of which year among the following has the same property?
 

  1. 2017
  2. 2016
  3. 2018
  4. 2015

Answer (Detailed Solution Below)

Option 1 : 2017

Clock and Calendar Question 7 Detailed Solution

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Logic: If we see carefully we can find that these dates have property  

3rd April, 2005 - 03/04/05  

6th August, 2010 - 06/08/10

5th December, 2013 - 05/12/13

Similarly,

Independence day 2017 - 15 August 2017 - 15/08/17

By above logic:  

No other option satisfy the above condition. So, Indian Independence Day of 2017 has the same property.

Hence, option 1) is the correct answer.

What will be the acute angle between the hour-hand and the minute-hand at 2:13 p.m?

  1. 16.5° 
  2. 18°
  3. 13.5° 
  4. 11.5° 

Answer (Detailed Solution Below)

Option 4 : 11.5° 

Clock and Calendar Question 8 Detailed Solution

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Formula Used:

Θ = | Hours × 30 × Minute |

Calculation:

Θ = | 2 × 30◦  × 13 |

Θ = | 60◦ |

Θ = | 60◦ - 71.5 |

Θ = | - 11.5 |

Θ = 11.5 

Hence, "11.5"  will be the acute angle between the hour-hand and the minute-hand at 2:13 p.m

What is the measure of the angle formed by the hands of the clock at 2'o clock?

  1. 30º
  2. 45º
  3. 60º
  4. 90º

Answer (Detailed Solution Below)

Option 3 : 60º

Clock and Calendar Question 9 Detailed Solution

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Calculation:   

The angle between two digits = 30° 

⇒ At 2'o clock one hand will be on 12 and second hand will be on 2 So, 30° × 2 = 60° 

∴ At 2'o clock angles between hands will be 60°.

The correct option is 3 i.e. 60° 

January 1, 2018 was Monday. Then January 1, 2019 falls on the day:

  1. Tuesday
  2. Wednesday
  3. Thursday
  4. Saturday

Answer (Detailed Solution Below)

Option 1 : Tuesday

Clock and Calendar Question 10 Detailed Solution

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Given - 

January 1, 2018 was Monday

Concept used - 

in a normal year number of days = 365

number of odd days = (365/7) = + 1

Solution - 

1 January 2018 = Monday

1 January 2019 = Monday + 1 = Tuesday

∴ January 1, 2019 = Tuesday  

Directions: Question below is followed by two statements, I and II. Read the statements given and mark the answer.

Is it Friday today?

I. February 15 of this year was a Wednesday.

II. Today is March 12.

  1. Question can be answered by statement I alone.
  2. Question can be answered by statement II alone.
  3. Question can be answered by using both statements together, but cannot be answered using either statement alone.
  4. Question cannot be answered even by using both statements together.

Answer (Detailed Solution Below)

Option 4 : Question cannot be answered even by using both statements together.

Clock and Calendar Question 11 Detailed Solution

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Statement I: February 15 of this year was a Wednesday: We cannot get what is today’s date.

Statement II: Today is March 12: We can’t tell which day today is, it can be any day.

Taking both the statements together: We cannot tell whether it is Friday or not because we don’t know if the year is leap year or not.

Hence both the statements were not enough to give the answer.

15th October 1984 will fall on which of the following days?

  1. Monday
  2. Tuesday

  3. Wednesday
  4. Thursday

Answer (Detailed Solution Below)

Option 1 : Monday

Clock and Calendar Question 12 Detailed Solution

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The logic followed here is:

1600 years contain 0 odd day, 300 years contain 1 odd day. Also, 83 years contain 20 leap years and 63 ordinary years and therefore (40+0) odd days i.e., 5 odd days.

∴ 1983 years contain (0 + 1 + 5) i.e., 6 odd days.

Number of days from Jan. 1984 to 15th Oct. 1984

= (31 + 29 + 31 + 30 + 31 + 30 +31+ 31 + 30 + 15)

= 289 days = 2 odd days

∴ Total number of odd days = 6 + 2 = 1 odd days.

So, 15th Oct, 1984 was Monday.

Hence, the correct answer is "Monday".

 

Find the approximate angle between the minute hand and the hour hand of a 12-hour clock when the time is 9 ∶ 25.

  1. 150 degrees
  2. 100 degrees
  3. 190 degrees
  4. 130 degrees

Answer (Detailed Solution Below)

Option 4 : 130 degrees

Clock and Calendar Question 13 Detailed Solution

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Given: a 12-hour clock when the time is 9 ∶ 25.

Formula used:

where H represents hour and M represents minutes.

Calculation:

Thus, the approximate angle between the minute hand and the hour hand is ' '.

If on January 20, 2030 is Sunday, then which day will be on January 4, 2028?

  1. Monday
  2. Sunday
  3. Tuesday
  4. Saturday

Answer (Detailed Solution Below)

Option 3 : Tuesday

Clock and Calendar Question 14 Detailed Solution

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Given:

⇒ January 20, 2030 = Sunday

⇒ January 22, 2030 = Tuesday

As, for each month dates 1, 8, 15, 22 and 29 comes on same week day.

⇒ January 1, 2030 = Tuesday

⇒ January 4, 2030 = Friday

⇒ January 4, 2029 = Thursday

As after every leap year, dates will move two days further and 2028 is a leap year. Leap year is a year which is divisible by 4 and having 366 days.

∴ January 4, 2028 = Tuesday

Choose the most appropriate answer.

At how many distinct points in a watch do the hour and the minute hand meet in an analogue clock? 

  1. 10
  2. 11
  3. 12
  4. 13

Answer (Detailed Solution Below)

Option 2 : 11

Clock and Calendar Question 15 Detailed Solution

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Calculation 

The hands of a clock meet once every hour but

Between 11:00 and 1:00'o clock, they coincide only once.

Therefore, the hands of a clock meet 11 times in 12 hours.

∴ The correct answer is 11 points.

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