Design of Steel Structures MCQ Quiz in বাংলা - Objective Question with Answer for Design of Steel Structures - বিনামূল্যে ডাউনলোড করুন [PDF]
Last updated on Apr 20, 2025
Latest Design of Steel Structures MCQ Objective Questions
Top Design of Steel Structures MCQ Objective Questions
Design of Steel Structures Question 1:
Horizontal web stiffener are used in plate girders if depth to thickness ratio of web is greater than
Answer (Detailed Solution Below)
Design of Steel Structures Question 1 Detailed Solution
Concepts:
As per IS 800:2007:
If
d/tw
85ϵ w
d/tw > 200; Horizontal stiffeners are provided.
In all above cases; d is the depth of web and tw is thickness of web.
Note:
The different type of stiffeners and their function is given below in tabulated form:
|
Stiffener |
Function |
|
Bearing stiffener |
To prevent Web Crushing at the location of heavy concentrated loads. |
|
Tension Stiffener |
To transfer tensile forces from flange to web |
|
Load Carrying Stiffener |
To prevent Web buckling due to any concentrated load. |
|
Torsional Stiffener |
To restrain girder against torsional effects at supports. |
|
Diagonal Stiffener |
Strengthen of web under the combination of bending and shear |
|
Horizontal Stiffener |
To prevent Web buckling against compressive force due to bending |
Design of Steel Structures Question 2:
As per ‘Indian Standard General Construction in Steel- Code of practice’ for deep penetration welds, where the depth of penetration beyond the root run is a minimum of 2.4 mm, the size of fillet should be as:
Answer (Detailed Solution Below)
Design of Steel Structures Question 2 Detailed Solution
Explanation:
As per IS 800: 2007 -
- The size of normal fillets shall be taken as the minimum weld leg size.
- For deep penetration welds, where the depth of penetration beyond the root run is a minimum of 2.4 mm, the size of the fillet should be taken as the minimum leg size plus 2.4 mm.
- For fillet welds made by semi-automatic or automatic processes, where the depth of penetration is considerably in excess of 2.4 mm, the size shall be taken considering the actual depth of penetration.
- The size of fillet welds shall not be less than 3 mm.\
- The minimum size of the weld is based on the thickness of the thicker plate being connected as shown in the below-tabulated form:
|
Thickness of thicker plate connected (mm) |
≤ 10 mm |
11-20 mm |
21-32 mm |
> 32 mm |
|
Minimum size of the weld (mm) |
3 mm |
5 mm |
6 mm |
8 mm |
Design of Steel Structures Question 3:
In case of welds using lap joints, the minimum lap should not be less than four times the thickness of the thinner part joined or t mm, whichever is more, where t (mm) is:
Answer (Detailed Solution Below)
Design of Steel Structures Question 3 Detailed Solution
Concept:
(i) For the size of the weld:
Minimum size of weld:
|
t (mm) |
0 - 10 |
11-20 |
21-32 |
32-50 |
|
Smin(mm) |
3 |
5 |
6 |
8 |
The minimum size of the weld is required to avoid stress concentration in welds.
Maximum size of weld:
Smax = t - 1.5 mm for pointed edge
Where t is the thickness of the thicker member
The size of welded is limited to ensure uniform stress distribution.
(ii) Length of weld/lap of length
Lp min = 4t or 40 mm (as per WSM)
= 5t or 50 mm (as per LSM)
Design of Steel Structures Question 4:
The permissible bending stress in the slab base of steel columns for all grades of steel is limited to
Answer (Detailed Solution Below)
Design of Steel Structures Question 4 Detailed Solution
Permissible stresses in steel structure members:
|
S.No. |
Types of stress |
Permissible stress (MPa) |
Factor of safety |
|
1 |
Axial Tensile stress |
0.6 fy |
1.67 |
|
2 |
Maximum axial compressive stress |
0.6 fy |
1.67 |
|
3 |
Bending tensile stress |
0.66 fy |
1.515 |
|
4 |
Maximum bending compressive stress |
0.66 fy |
1.515 |
|
5 |
Average shear stress |
0.4 fy |
2.5 |
|
6 |
Maximum shear stress |
0.45 fy |
2.22 |
|
7 |
Bearing stress |
0.75 fy |
1.33 |
|
8 |
Stress in slab base |
185 |
- |
∴ The permissible bending stress in the slab base of steel columns for all grades of steel is limited to 185.
Design of Steel Structures Question 5:
As per IS 800 : 2007, the value of imperfection factor for buckling class "b" is
Answer (Detailed Solution Below)
Design of Steel Structures Question 5 Detailed Solution
Concept:
Imperfection Factor: It takes into account, the imperfection that may occur while load transferring, fabrication, or installation.
It depends upon the shape of the column cross-section under consideration, the direction in which buckling can occur, and the fabrication process (hot rolled, welded or cold-formed).
Classification of different sections under different buckling class i.e. a, b, c or d used for the design of axial compression member.
As per IS 800: 2007, Table 7;
|
Buckling Class |
a |
b |
c |
d |
|
α |
0.21 |
0.34 |
0.49 |
0.76 |
∴ The imperfection factor for buckling class b is 0.34
Design of Steel Structures Question 6:
The permissible maximum deflection of a purlin of 4.5 m which is subjected to live load supporting GI metal sheet and supported by elastic cladding is:
Answer (Detailed Solution Below)
Design of Steel Structures Question 6 Detailed Solution
Vertical Deflection limits for industrial buildings as per IS 800:2007 are:
a) For Purlins and Girts subjected to live load/wind load supported on elastic cladding, maximum deflection is limited to span / 150.
b) For Purlins and Girts subjected to live load/wind load supported on Brittle cladding, maximum deflection is limited to span / 180.
Calculation:
∴ Permissible maximum deflection = Span/150 = 4500/150 = 30 mm
Design of Steel Structures Question 7:
Calculate the effective length of column having c/c length of 4m and both ends are fixed as per IS 800-2007.
Answer (Detailed Solution Below)
Design of Steel Structures Question 7 Detailed Solution
Explanation:
As per IS: 800 - 2007
The design value of the effective length factor for various combinations is given below:
Given both ends are fixed
So the Case becomes Restrained in all movements
So effective length = 0.65 × L = 0.65 × 4 = 2.6 m
Design of Steel Structures Question 8:
The shape factor for circular section is ______.
Answer (Detailed Solution Below)
Design of Steel Structures Question 8 Detailed Solution
Explanation:
Shape factor:
The shape factor is defined as the ratio of the fully plastic moment to yield moment of section. Shape factor depend upon cross-section.
Some standard shape factors are as follows:
| Triangular | 2.34 |
| Rectangular | 1.5 |
| Circular | 1.7 |
| Diamond | 2 |
| Hollow Circular | 1.27 |
Design of Steel Structures Question 9:
The design strength of a tension member is given by a minimum of
i) Block shear strength of end region
ii) Rupture of critical section
iii) Yielding of net section
Which of the above statements(s) is/are correct?
Answer (Detailed Solution Below)
Design of Steel Structures Question 9 Detailed Solution
As per IS 800: 2007 codal provisions Design strength of tension member is the minimum of the following:
1. Design strength due to yielding of Gross section.
2. Design strength due to Rupture of Net Section.
3. Block Shear Strength
Hence, Statement 3 is false as such Design strength of tension member is based on the yielding of Gross section and not net section.
Important Point:
Design strength due to Rupture of Net Section for plates is based on net effective area at critical section and for angle section is based on shear lag effect.
Design of Steel Structures Question 10:
When gantry girders carry moving loads such as charging cars, the deflection should not exceed
Answer (Detailed Solution Below)
Design of Steel Structures Question 10 Detailed Solution
Explanation:
AS per IS 800(2007) (C- 5.6.1 Dejection)
|
Types of Gantry Girder |
Permissible Deflection |
|
When cranes are manually operated |
L/500 |
|
When cranes are travelling overhead and operated electrically up to 500 KN |
L/750 |
|
When cranes are travelling overhead and operated electrically over 500 KN |
L/1000 |
|
Other moving loads such as charging cars etc. |
L/600 |